Six Canadian and 6 Mexican delegates attend an international trade conference. A three-delegate committee will be selected from the 12 delegates. How many three-delegate committees can be formed if each possible committee must include at least one Mexican delegate?
A) 260
B) 240
C) 220
D) 200
E) 20
So you are saying 12 pick 3 minus 6 pick 3?
ReplyDeletewhat is the final answer?
ReplyDeleteI concur with Bhushan's solution, but what is wrong with 6C1 X 11C2=330 (Means 1 Mexican for sure the other 2 can be picked from the remaining 11).
ReplyDeleteBlaoism's solution also makes sense:
12C3 - 6C3
Look at it in another way
M _ _ = 2nd spot can be filled 11 and 3rd 10 ways. That gives you 110.(Wouldnt this cover the 2M and 3M cases). I know the correct way is to branch it out as Bhushan and Blaoism have done.