Two things will solve this guy faster: 1) know that a regular hexagon can be divided into six equal equilateral triangles, 2) know the formula used to calculate the area of an equilateral triangle using the side as a variable.
area of an equil triangle is [(side^2)*(sq root 3)]/4. so 6*[(side^2)*(sq root 3)]/4 = 24*(sq root 3). Solve for side = 4, which also = radius of circle. pi r^2 = 16 pi.
Two things will solve this guy faster: 1) know that a regular hexagon can be divided into six equal equilateral triangles, 2) know the formula used to calculate the area of an equilateral triangle using the side as a variable.
ReplyDeleteAnswer is D
ReplyDeleteI am getting 32Pi..
ReplyDeletearea of equilateral triangle = 4root3
=0.5 X x/2 X (root3)/2 X x
x=4root2
area of circle = pi x X x
= 32pi
what gives?
area of an equil triangle is [(side^2)*(sq root 3)]/4. so 6*[(side^2)*(sq root 3)]/4 = 24*(sq root 3). Solve for side = 4, which also = radius of circle. pi r^2 = 16 pi.
ReplyDelete